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Two SumEasy

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

Example:

Input: nums = [2,7,11,15], target = 9 Output: [0,1]

Constraints:

2 <= nums.length <= 10^4

-10^9 <= nums[i] <= 10^9

Python
Run
1def two_sum(nums, target):
2 seen = {}
3 for i, num in enumerate(nums):
4 comp = target - num
5 if comp in seen:
6 return [seen[comp], i]
7 seen[num] = i
8

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What data structure gives you O(1) lookups?
I'd use a hash map to store complements...
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1def solve(self, nums):
2 seen = {}
3 for n in nums:
4 if n in seen:
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ClientLBAPICacheDB
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Problem Solving85
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Two SumGoogle
Easy
LRU CacheMeta
Medium
Merge K ListsAmazon
Hard
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42:15
Merge IntervalsMedium

Given an array of intervals where intervals[i] = [start_i, end_i], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input.

Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]]
1def merge(self, intervals):
2 intervals.sort(key=lambda x: x[0])
3 merged = [intervals[0]]
4 for start, end in intervals[1:]:
5 if start <= merged[-1][1]:
6 merged[-1][1] = max(merged[-1][1], end)
7 else:
8 merged.append([start, end])
9 return merged
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